INVERSE SQUARE PROBLEMS

 

If a radiographer receives  50mR of exposure at 3 feet from a source for one hour, how much will the radiographer receive if he moves four feet from the source.

 

Hints to solve this problem:

 

A) Identify the formula

B)  Place the factors in the problem into the formula

C)   Ask yourself : With the change proposed in the problem, would the radiographer receive more or less exposure

D) Calculate the problem

E)  Did the answer agree with the change you predicted?

 

 

A)       I1       ( D2) squared

           I2        (D1) squared

 

B)   What is   I1?                   50mR

      What is  I2 ?                    X

       What is D2?                    4 feet

       What is D1?                    3 feet       

 

C)  less

 

D) 50            4 feet squared

     X             3 feet squared

 

    50            16 feet

    X               9 feet

 

 

   16X = 450

      X =28 mR

 

E)  yes, the exposure rate when down.

 

TRY THIS!!

       

If a radiographer receives  50mR of exposure at 3 feet from a source for one hour, how much will the radiographer receive if he moves two feet from the source and stays in for only 20 minutes.

 

A) Identify the formula

B)  Place the factors in the problem into the formula

C)   Calculate the problem and decide, without factoring in the time at this point , if the exposure rate will increase or decrease

D)  Take you answer to the inverse square problem and now factor in the time difference

 

A)       I1       ( D2) squared

           I2        (D1) squared

 

B)   What is   I1?                   50mR

      What is  I2 ?                    X

       What is D2?                    2 feet

       What is D1?                    3 feet       

 

C)   Exposure should increase!

    50            2 feet squared

     X             3 feet squared

 

    50            4 feet

    X               9 feet

 

 

   4X = 450

      X = 112.5mR  PER HOUR

 

d)  The tech was only in the room for 20 minutes with this new exposure versus one hour.

   

     20 minutes/60 minutes = 0.33

     112.5mr x 0.33 = 37.12 mR