AMATYC SML Training Session –
October 1, 2009
As
always, these will be posted, with solution, to my website: www.montgomerycollege.edu/~rpenn
Additional
problems are available at the AMATYC website, http://www.amatyc.org
A. 2/5 B. -2/5 C. 5/2 D.
-5/2 E. -2
Solving for y, y=2/5 x -2, so its slope is 2/5, and
that would also be the slope of any line parallel to it.
A.
19 B. 55 C. 75 D.
107 E. 163
f(3)=7,
f(7)=19, f(19)=55
A. -4 B. ¼ C. 7 D. 11 E.
20
2x-8 = 6 -> x=7
A. 5 B. 12 C. 48 D. 182 E. 210
f(1)=8 -> a+b=8.
f(g(50))-g(f(50))=
28 -> (50ab+a2 + b)-(50ab+b2+a) = 28 -> a2-b2
+ b-a = 28 -> (a+b)(a-b)-(a-b) = (a+b-1)(a-b)=28
Since a+b=8, a+b-1=7, so
7(a-b)=28, or a-b=4.
This then tells us that a=6 and b=2, so ab=12
which of the
following must be true about M and N for all nonzero choices of a, b, and c?
A. The x-intercepts are equal B. The y-intercepts are equal
C. The slopes are equal D.
The slopes are opposite
E.
The slopes are reciprocals
The slope of each reflection is the opposite of the
slope of L, so M and N have the same slope – C
(an easy way to see that C is
the answer is to draw a “typical” line L, and then visually draw M and N)
A. x-2 B. x+2 C. x-1 D.
x+1 E. x-3
(x-a) is a factor if and only if a
is a root, which is also the same as saying that the
graph of the polynomial hits the x-axis at a.
Graphing this, we see it crosses the x-axis at 2, -2,
1 and 3 but not -1, so D is the answer.
(btw – if you are using a
TI-89, you can just ask it to factor the polynomial for you!)
A. -12 B. 0 C. 4 D. 6 E. 12
This is the same as asking for the value of the
polynomial when x=-2. This is -12.
If a
weekly subscription costs between $2.20 and $2.30, what is the cost of one
Sunday paper and one daily paper?
A. 56¢ B. 81¢ C. 84¢ D. 87¢ E.
$1.12
S=2D.
1 week is 1S+6D = 8D, and the only number in the given
range divisible by 8 is $2.24, which corresponds to $.28 / day.
So 1S and 1D costs $.84
A. -2 B. -1 C. 2 D. 7 E. 9
When you distribute the product, the quadratic terms
come from (x2)(-1), (3x)(3x), and (-1)(x2),
so the coefficient is 7.
A.
B.
C.
D.
E. ![]()
For
simplicity, let x=102009.
(x+1)2+(x+2)2-x2 = x2 +2x+1+
x2 +4x+4- x2 = x2 +6x+5 = (x+1)(x+5), so D.
What
is the remainder when (x-1)P(x) is divided by (x-1)
(x-2)2 ?
A.
3x-3 B. 3x2 – 6x + 3 C. 3 D.
x-1 E. x-2
B. The easiest
way to see this: Let P(x) = 3x-3. Then P(x)/(x-2)2 = 0 with a
remainder of x-3, and
(x-1)P(x)/ ((x-1)(x-2)2) = 0 with a remainder
of (x-3)(x-1) = B